y^2-10y+40=0

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Solution for y^2-10y+40=0 equation:


Simplifying
y2 + -10y + 40 = 0

Reorder the terms:
40 + -10y + y2 = 0

Solving
40 + -10y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -10y + -40 + y2 = 0 + -40

Reorder the terms:
40 + -40 + -10y + y2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -10y + y2 = 0 + -40
-10y + y2 = 0 + -40

Combine like terms: 0 + -40 = -40
-10y + y2 = -40

The y term is -10y.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10y + 25 + y2 = -40 + 25

Reorder the terms:
25 + -10y + y2 = -40 + 25

Combine like terms: -40 + 25 = -15
25 + -10y + y2 = -15

Factor a perfect square on the left side:
(y + -5)(y + -5) = -15

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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